Skip to main content

Posts

Showing posts from December, 2013

Two goods train each 500 m long, are running in opposite directions on parallel tracks. Their speeds are 45 km/hr and 30 km/hr respectively. Find the time taken by the slower train to pass the driver of

Two goods train each 500 m long, are running in opposite directions on parallel tracks. Their speeds are 45 km/hr and 30 km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one. A. 12 sec B. 24 sec C. 48 sec D. 60 sec Answer:  Option  B Explanation: Relative speed = = (45 + 30) km/hr = 75 x 5 m/sec 18 = 125 m/sec. 6 We have to find the time taken by the slower train to pass the DRIVER of the faster train and not the complete train. So, distance covered = Length of the slower train. Therefore, Distance covered = 500 m.  Required time = 500 x 6 = 24 sec. 125

How many seconds will a 500 metre long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr?

How many seconds will a 500 metre long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr? A. 25 B. 30 C. 40 D. 45 Answer:  Option  B Explanation: Speed of the train relative to man = (63 - 3) km/hr = 60 km/hr = 60 x 5 m/sec 18 = 50 m/sec. 3  Time taken to pass the man = 500 x 3 sec 50 = 30 sec.

A train moves past a telegraph post and a bridge 264 m long in 8 seconds and 20 seconds respectively. What is the speed of the train?

A train moves past a telegraph post and a bridge 264 m long in 8 seconds and 20 seconds respectively. What is the speed of the train? A. 69.5 km/hr B. 70 km/hr C. 79 km/hr D. 79.2 km/hr Answer:  Option  D Explanation: Let the length of the train be  x  metres and its speed by  y  m/sec. Then, x = 8            x  = 8 y y Now, x  + 264 =  y 20  8 y  + 264 = 20 y   y  = 22.  Speed = 22 m/sec = 22 x 18 km/hr = 79.2 km/hr. 5

A train speeds past a pole in 15 seconds and a platform 100 m long in 25 seconds. Its length is:

A train speeds past a pole in 15 seconds and a platform 100 m long in 25 seconds. Its length is: A. 50 m B. 150 m C. 200 m D. Data inadequate Answer:  Option  B Explanation: Let the length of the train be  x  metres and its speed by  y  m/sec. Then, x = 15            y  = x . y 15 x  + 100 = x 25 15  15( x  + 100) = 25 x  15 x  + 1500 = 25 x  1500 = 10 x   x  = 150 m.

A 300 metre long train crosses a platform in 39 seconds while it crosses a signal pole in 18 seconds. What is the length of the platform?

A 300 metre long train crosses a platform in 39 seconds while it crosses a signal pole in 18 seconds. What is the length of the platform? A. 320 m B. 350 m C. 650 m D. Data inadequate Answer:  Option  B Explanation: Speed = 300 m/sec = 50 m/sec. 18 3 Let the length of the platform be  x  metres. Then, x  + 300 = 50 39 3  3( x  + 300) = 1950   x  = 350 m.

A train 800 metres long is running at a speed of 78 km/hr

A train 800 metres long is running at a speed of 78 km/hr. If it crosses a tunnel in 1 minute, then the length of the tunnel (in meters) is: A. 130 B. 360 C. 500 D. 540 Answer:  Option  C Explanation: Speed = 78 x 5 m/sec = 65 m/sec. 18 3 Time = 1 minute = 60 seconds. Let the length of the tunnel be  x  metres. Then, 800 +  x = 65 60 3  3(800 +  x ) = 3900   x  = 500.

A train travelling at a speed of 75 mph enters a tunnel 31/2 miles long

A train travelling at a speed of 75 mph enters a tunnel 3  miles long. The train is  mile long. How long does it take for the train to pass through the tunnel from the moment the front enters to the moment the rear emerges? A. 2.5 min B. 3 min C. 3.2 min D. 3.5 min Answer:  Option  B Explanation: Total distance covered = 7 + 1 miles 2 4 = 15 miles. 4  Time taken = 15 hrs 4 x 75 = 1 hrs 20 = 1 x 60 min. 20 = 3 min.