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Father is aged three times more than his son Ronit. After 8 years


Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
A.2 timesB.
2 1times
2
C.
2 3times
4
D.3 times


Answer: Option A
Explanation:
Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.
(4x + 8) =5(x + 8)
2
 8x + 16 = 5x + 40
 3x = 24
 x = 8.
Hence, required ratio =(4x + 16)=48= 2

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