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The average speed of a train in the onward journey is 25% more than that in the return journey. The train halts for one hour on reaching the destination. The total time taken for the complete to and from journey is 17 hours, covering a distance of 800 km

The average speed of a train in the onward journey is 25% more than that in the return journey. The train halts for one hour on reaching the destination. The total time taken for the complete to and from journey is 17 hours, covering a distance of 800 km. The speed of the train in the onward journey is:
[A] 45 km/hr
[B] 47.5 km/hr
[C] 52 km/hr
[D] 56.25 km/hr


ANS: D
Explanation:
Let the speed in return journey be x km/hr.
Then, speed in onward journey =(125/100)x = (5/4)x km/hr
So. Speed in onward journey = [(5/4)*45] km/hr = 56.25 km/hr
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Comments

  1. Unknown5 October 2016 at 18:58

    Let the speed in the return journey be x km/hr
    Thrn speed in onward journey=(125/100)x=(5/4)x km/hr
    Here time taken =17-1=16 hrs
    Then 400/x + 400×4/5x =16
    x=45
    SO, speed in onward journey={5/4*45}km/hr
    =56.25 Km/hr

    ReplyDelete
  2. Unknown2 August 2017 at 00:05

    This comment has been removed by the author.

    ReplyDelete
  3. Unknown6 August 2018 at 11:06

    Thanku more appropriate

    ReplyDelete

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