Skip to main content

The ratio of incomes of two person P1 and P2 is 5 : 4 and the ratio of their expenditures is 3 : 2. If at the end of the year, each saves Rs.1600, then what is the income of P1?

The ratio of incomes of two person P1 and P2 is 5 : 4 and the ratio of their expenditures is 3 : 2. If at
     the end of the year, each saves Rs.1600, then what is the income of P1?

     a)Rs.800 b) Rs.2400 c)Rs.4000 d)3200





























Expl : Let the income of P1 and P2  be Rs. 5x and Rs.4x respectively and let their
     expenditures be Rs.3y and 2y respectively.

     Then, 5x – 3y = 1600 …(i) and 4x – 2y = 1600 ……..(ii)

     On multiplying (i) by 2, (ii) by 3 and subtracting, we get : 2x = 1600 -> x = 800

     P1’s income = Rs 5*800 = Rs.4000

Comments

Popular posts from this blog

Find the number of perfect squares in the given series 2013, 2020, 2027,.

Find the number of perfect squares in the given series 2013, 2020, 2027,................, 2300   (Hint 44^2=1936) a. 1   b. 2    c. 3   d. Can’t be determined Answer: a Explanation: The given series is an AP with common difference of 7. So the terms in the above series are in the form of 2013 + 7k.  We have to find the perfect squares in this format in the given series. Given that 44^2 = 1936. Shortcut: To find the next perfect square, add 45th odd number to 44^2. So 45^2 = 1936 + (2 x 45 -1) = 2025 46^2 = 2025 + (2 x 46 - 1) = 2116 47^2 = 2116 + (2 x 47 - 1) = 2209 Now subtract 2013 from the above numbers and divide by 7. Only 2209 is in the format of 2013 + 7k.  One number satisfies.

It takes 10 days for digging a trench of 100 m long, 50 m broad and 10 m deep. What length of trench, 25 m broad and 15 m deep can be dug in 30 days ?

 It takes 10 days for digging a trench of 100 m long, 50 m broad and 10 m deep.  What length of trench, 25 m broad and 15 m deep can be dug in 30 days ?       a) 400 m          b) 200 m          c) 100 m          d) 89m Expl : More days, more length (Direct)       Less breadth, more length (Indirect)       More depth, less length (Indirect       Days      10 : 30;       Breadth  25 : 50;                  : : 100 : x       Depth    15 : 10;                     :. 10 * 25* 15 * x = 30 *50 * 10 *100             x= (30*50*10*100)/10*25*15 = 400      So the required length = 400m