Skip to main content

What is the greatest number of four digits which is divisible by 15, 25, 40 and 75 ?

What is the greatest number of four digits which is divisible by 15, 25, 40 and 75 ?
A. 9800 B. 9600
C. 9400 D. 9200



Answer: Option B
Greatest number of four digits = 9999

 LCM of 15, 25, 40 and 75 = 600

 9999 ÷ 600 = 16, remainder = 399

 Hence, greatest number of four digits which is divisible by 15, 25, 40 and 75
= 9999 - 399 = 9600

Comments

Post a Comment

Popular posts from this blog

Find the number of perfect squares in the given series 2013, 2020, 2027,.

Find the number of perfect squares in the given series 2013, 2020, 2027,................, 2300   (Hint 44^2=1936) a. 1   b. 2    c. 3   d. Can’t be determined Answer: a Explanation: The given series is an AP with common difference of 7. So the terms in the above series are in the form of 2013 + 7k.  We have to find the perfect squares in this format in the given series. Given that 44^2 = 1936. Shortcut: To find the next perfect square, add 45th odd number to 44^2. So 45^2 = 1936 + (2 x 45 -1) = 2025 46^2 = 2025 + (2 x 46 - 1) = 2116 47^2 = 2116 + (2 x 47 - 1) = 2209 Now subtract 2013 from the above numbers and divide by 7. Only 2209 is in the format of 2013 + 7k.  One number satisfies.
Post a Comment
Read more